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EXERCISE 6.1 · Q39

Q.Let ff be a subset of Z×ZZ\times Z defined by f={(ab,a+b):a,b∈Z}f=\{(ab,a+b): a,b\in Z\}. Is ff a function from ZZ to ZZ? Justify.

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f={(ab, a+b):a,b∈Z}f=\{(ab,\,a+b): a,b\in Z\}. For ff to be a function, the product abab (the first coordinate) must determine a unique sum a+ba+b (the second coordinate).

Take a=1,b=6a=1,b=6: ab=6ab=6, a+b=7a+b=7, giving the pair (6,7)(6,7).

Take a=2,b=3a=2,b=3: ab=6ab=6, a+b=5a+b=5, giving the pair (6,5)(6,5). …

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