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EXERCISE 6.1 · Q73

Q.Given that log⁡2=a\log 2=a and log⁡3=b\log 3=b, write log⁡96\log 96 in terms of aa and bb.

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96=32×3=25×396=32\times3=2^5\times3.

log⁡96=log⁡(25×3)=log⁡25+log⁡3=5log⁡2+log⁡3\log96=\log(2^5\times3)=\log2^5+\log3=5\log2+\log3 (product and power rules). …

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