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EXERCISE 6.1 · Q27

Q.Find the domain and range of the function g(x)=x+4x−2g(x)=\dfrac{x+4}{x-2}.

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g(x)=x+4x−2g(x)=\dfrac{x+4}{x-2}.

Domain: need x−2≠0x-2\ne0, so x≠2x\ne2; Domain =R−{2}=R-\{2\}.

Range: let y=x+4x−2y=\dfrac{x+4}{x-2}. Then y(x−2)=x+4  ⟹  xy−2y=x+4  ⟹  x(y−1)=4+2y  ⟹  x=4+2yy−1y(x-2)=x+4 \implies xy-2y=x+4 \implies x(y-1)=4+2y \implies x=\dfrac{4+2y}{y-1}. …

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