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EXERCISE 6.1 · Q9

Q.Check if the relation given by the equation represents yy as a function of xx.\ x+y2=9x+y^2=9

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x+y2=9  ⟹  y2=9−x  ⟹  y=±9−xx+y^2=9 \implies y^2=9-x \implies y=\pm\sqrt{9-x} (for x≤9x\le9).

For any x<9x<9, both y=9−xy=\sqrt{9-x} and y=−9−xy=-\sqrt{9-x} satisfy the equation — two different yy-values for the same xx. That means xx does not determine a unique yy, so yy is not a function of xx (this is …

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