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Mathematics · Ch 15 — Functions

Value of a Function

15.1.4

Value of a Function

Value of a function. f(a)f(a) is called the value of the function f(x)f(x) at x=ax=a — simply the result of substituting x=ax=a into the formula for ff.

Ex. 1 (Evaluation): Evaluate f(x)=2x2−3x+4f(x)=2x^2-3x+4 at x=7x=7 and x=−2tx=-2t.

Solution: f(7)=2(7)2−3(7)+4=2(49)−21+4=98−21+4=81f(7)=2(7)^2-3(7)+4=2(49)-21+4=98-21+4=81.

f(−2t)=2(−2t)2−3(−2t)+4=2(4t2)+6t+4=8t2+6t+4f(-2t)=2(-2t)^2-3(-2t)+4=2(4t^2)+6t+4=8t^2+6t+4.

Ex. 2 (Reading values off a graph): Using the graph of y=g(x)y=g(x) (Fig. 6.14), find g(−4)g(-4) and g(3)g(3).

Solution: From the graph, when x=−4x=-4, y=0y=0, so g(−4)=0g(-4)=0. When x=3x=3, y=−5y=-5, so g(3)=−5g(3)=-5.

Ex. 3 (Solving 'backwards' from an output, algebraically): If t(m)=3m2−mt(m)=3m^2-m and t(m)=4t(m)=4, find mm.

Solution: 3m2−m=4  ⟹  3m2−m−4=03m^2-m=4 \implies 3m^2-m-4=0. Factor by splitting the middle term: 3m2−4m+3m−4=0  ⟹  m(3m−4)+1(3m−4)=0  ⟹  (3m−4)(m+1)=03m^2-4m+3m-4=0 \implies m(3m-4)+1(3m-4)=0 \implies (3m-4)(m+1)=0. So m=43m=\dfrac43 or m=−1m=-1.

Ex. 4 (Solving 'backwards' from a graph): From the graph below (Fig. 6.15), find xx for which f(x)=4f(x)=4.

Solution: Solving f(x)=4f(x)=4 means finding where the graph meets the horizontal line y=4y=4. Reading the intersection points off the graph (Fig. 6.16), the line y=4y=4 meets the curve at x=−1x=-1 and x=3x=3. So x=−1x=-1 and x=3x=3. …

Figure 1Fig. 6.14 — reading g(-4) and g(3) off a graph (Ex. 2)

What this figure shows. The graph of a function y=g(x) drawn as a curve or set of line segments, with dashed guide lines dropped from x=-4 up (or down) to the curve and then across to the y-axis reading off the value g(-4)=0, and similarly from x=3 to the curve and across to read g(3)=-5. Demonstrates evaluating a function directly from its picture rather than from a for …

Figure 2Fig. 6.15 and Fig. 6.16 — solving f(x)=4 from a graph (Ex. 4)

What this figure shows. The graph of a function y=f(x) together with the horizontal line y=4 drawn across it; Fig. 6.16 highlights the two points where this horizontal line actually intersects the curve, with dashed guide lines dropped down to the x-axis showing the corresponding x-values x=-1 and x=3. Demonstrates the reverse process to Fig. 6.14: given an output value, read off every input that produces …