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EXERCISE 6.1 · Q40

Q.Check the injectivity and surjectivity of the following function: f:N→Nf:N\to N given by f(x)=x2f(x)=x^2.

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f:N→Nf:N\to N, f(x)=x2f(x)=x^2.

Injective: for x1,x2∈Nx_1,x_2\in N (positive), f(x1)=f(x2)  ⟹  x12=x22  ⟹  x1=x2f(x_1)=f(x_2) \implies x_1^2=x_2^2 \implies x_1=x_2 (since both are positive, only the positive square root applies). So ff is one-one. …

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