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EXERCISE 6.1 · Q66

Q.Write the following expression as a sum or difference of logarithms: log⁡(pqrs)\log\left(\dfrac{pq}{rs}\right).

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log⁡(pqrs)=log⁡(pq)−log⁡(rs)\log\left(\dfrac{pq}{rs}\right)=\log(pq)-\log(rs) (quotient rule)

=(log⁡p+log⁡q)−(log⁡r+log⁡s)=(\log p+\log q)-(\log r+\log s) (product rule on each piece) …

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