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Try this 10.5.5 · Q1

Q.
  1. Draw structures of enantiomers of lactic acid (CH₃-CH(OH)-COOH) using Fischer projection formulae.
  2. Draw structures of enantiomers of 2-bromobutane using wedge formula.

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  • 1. Lactic acid — put COOH at the top and CH₃ at the bottom of the vertical line; one enantiomer has H left, OH right, the other OH left, H right. The two crosses are mirror images.
  • 2. 2-Bromobutane — central C with CH₃ up (plain line), C₂H₅ down (solid wedge toward you); in one enantiomer H is on the hashed bond left and Br plain right, in the mirror image Br left and H hashed right — the same …

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