Try this 10.5.5 · Q1
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- Draw structures of enantiomers of lactic acid (CH₃-CH(OH)-COOH) using Fischer projection formulae.
- Draw structures of enantiomers of 2-bromobutane using wedge formula.
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Start your 14-day free trial to unlock the full solution →- 1. Lactic acid — put COOH at the top and CH₃ at the bottom of the vertical line; one enantiomer has H left, OH right, the other OH left, H right. The two crosses are mirror images.
- 2. 2-Bromobutane — central C with CH₃ up (plain line), C₂H₅ down (solid wedge toward you); in one enantiomer H is on the hashed bond left and Br plain right, in the mirror image Br left and H hashed right — the same …
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