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Exercise 2.3 · Q44

Q.Check the validity of the Rolle's theorem for the function f(x)=x2−4x+3, x∈[1,3]f(x) = x^2 - 4x + 3,\ x \in [1, 3].

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✓ Free question

f(x)=x2−4x+3f(x)=x^2-4x+3 is a polynomial, hence continuous on [1,3][1,3] and differentiable on (1,3)(1,3).

f(1)=1−4+3=0f(1)=1-4+3=0. f(3)=9−12+3=0f(3)=9-12+3=0. So f(1)=f(3)=0f(1)=f(3)=0 — all hypotheses of Rolle's theorem are satisfied.

f′(x)=2x−4f'(x)=2x-4. Setting f′(c)=0f'(c)=0: 2c−4=0⇒c=22c-4=0\Rightarrow c=2, and 2∈(1,3)2\in(1,3).

✓Final answer

Rolle's theorem holds; c=2∈(1,3)c = 2 \in (1,3)

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