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Exercise 2.3 · Q59

Q.Verify Lagrange's mean value theorem for the function f(x)=x2−3x−1, x∈[−117,137]f(x) = x^2 - 3x - 1,\ x \in \left[-\dfrac{11}{7}, \dfrac{13}{7}\right].

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f(x)=x2−3x−1f(x)=x^2-3x-1 is a polynomial, continuous and differentiable everywhere.

f(−117)=12149+337−1=121+231−4949=30349f\left(-\tfrac{11}7\right)=\tfrac{121}{49}+\tfrac{33}{7}-1=\tfrac{121+231-49}{49}=\tfrac{303}{49}.

f(137)=16949−397−1=169−273−4949=−15349f\left(\tfrac{13}7\right)=\tfrac{169}{49}-\tfrac{39}{7}-1=\tfrac{169-273-49}{49}=-\tfrac{153}{49}.

Chord slope =−153/49−303/4913/7−(−11/7)=−456/4924/7=−45649×724=−197=\dfrac{-153/49-303/49}{13/7-(-11/7)}=\dfrac{-456/49}{24/7}=-\dfrac{456}{49}\times\dfrac{7}{24}=-\dfrac{19}{7}. …

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