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Exercise 2.1 · Q18

Q.The edge of a cube is decreasing at the rate of 0.60.6 cm/sec. Find the rate at which its volume is decreasing when the edge of the cube is 22 cm.

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Let xx be the edge, V=x3V=x^3 the volume. dVdt=3x2dxdt\dfrac{dV}{dt}=3x^2\dfrac{dx}{dt}.

Since the edge is decreasing, dxdt=−0.6\dfrac{dx}{dt}=-0.6 cm/sec. At x=2x=2:

dVdt=3(4)(−0.6)=−7.2\dfrac{dV}{dt}=3(4)(-0.6)=-7.2 cm³/sec. …

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