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Miscellaneous Exercise 2(II) · Q116

Q.The position of a particle is given by the function s(t)=2t2+3t−4s(t) = 2t^2 + 3t - 4. Find the time t=ct = c in the interval 0≤t≤40 \le t \le 4 when the instantaneous velocity of the particle equals to its average velocity in this interval.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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s(t)=2t2+3t−4s(t)=2t^2+3t-4. s(0)=−4s(0)=-4. s(4)=32+12−4=40s(4)=32+12-4=40.

Average velocity over [0,4]=s(4)−s(0)4−0=40−(−4)4=444=11[0,4]=\dfrac{s(4)-s(0)}{4-0}=\dfrac{40-(-4)}{4}=\dfrac{44}{4}=11.

Instantaneous velocity v(t)=s′(t)=4t+3v(t)=s'(t)=4t+3. …

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