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Exercise 2.1 · Q23

Q.If water is poured into an inverted hollow cone whose semi-vertical angle is 30°30°, so that its depth (measured along the axis) increases at the rate of 1 cm/sec. Find the rate at which the volume of water increasing when the depth is 2 cm.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Let hh = depth of water, rr = radius of the water surface. Since the semi-vertical angle is 30°30°: r=htan⁡30°=h3r=h\tan30°=\dfrac{h}{\sqrt3}.

V=13πr2h=13π(h23)h=πh39V=\dfrac13\pi r^2h = \dfrac13\pi\left(\dfrac{h^2}{3}\right)h = \dfrac{\pi h^3}{9}.

dVdt=π9(3h2)dhdt=πh23dhdt\dfrac{dV}{dt}=\dfrac{\pi}{9}(3h^2)\dfrac{dh}{dt}=\dfrac{\pi h^2}{3}\dfrac{dh}{dt}. …

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