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Question 68 of 90

Q.Find the wavelength at which a black body radiates maximum energy, if its temperature is 427°C. (Wein's constant b = 2.898×10−32.898\times10^{-3} mK)

(a) 0.0414×10−60.0414\times10^{-6} m
(b) 4.14×10−64.14\times10^{-6} m
(c) 41.4×10−641.4\times10^{-6} m
(d) 414×10−6414\times10^{-6} m
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017MCQ· 1mImportance★★★★★
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Wien's displacement law: λmT=b\lambda_m T = b.

Wien's displacement law states that the wavelength at which a black body radiates maximum energy is inversely proportional to its absolute temperature:

λmT=b\lambda_m T = b

Here T=427 ∘C=427+273=700 KT = 427\,^{\circ}\text{C} = 427 + 273 = 700\ \text{K} and b=2.898×10−3 m Kb = 2.898\times10^{-3}\ \text{m K}.

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