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7.6 Q.I · Q73

Q.lim⁡x→0[5x+3x−2x−1x]\displaystyle\lim_{x\to 0}\left[\frac{5^x+3^x-2^x-1}{x}\right]

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✓ Free question

Write 5x+3x−2x−1=(5x−1)+(3x−1)−(2x−1)5^x+3^x-2^x-1=(5^x-1)+(3^x-1)-(2^x-1). Dividing by xx: log⁡5+log⁡3−log⁡2=log⁡5×32=log⁡152\log5+\log3-\log2=\log\dfrac{5\times3}{2}=\log\dfrac{15}{2}.

✓Final answer

log⁡(15/2)\log(15/2)

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