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Q.The electrical resistance of a conductor (A) varies directly proportional to its area of cross-section. (B) decreases with increase in its temperature. (C) decreases with increase in its conductivity. (D) is independent of its shape but depends only on its volume.

CBSECBSE Class XII Board 2020MCQ· 1mImportance★★★★★
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Resistance depends on the material's resistivity, length, and cross-sectional area (R=ρLAR = \rho \frac{L}{A}). Conductivity is the reciprocal of resistivity, so higher conductivity means lower resistance — making option (C) correct.

The key to this question is the definition of electrical resistance and how it relates to the physical properties of a conductor. You need to recall the formula that ties resistance to geometry and material.

The fundamental relation is:

R=ρLAR = \rho \frac{L}{A}

where RR is resistance, ρ\rho is the resistivity (a material property), LL is the length, and AA is the cross-sectional area. Resistivity ρ\rho is the inverse of conductivity σ\sigma: ρ=1/σ\rho = 1/\sigma.

Now let's examine each option carefully.

  1. Option (A): "varies directly proportional to its area of cross-section."

    From R=ρL/AR = \rho L / A, resistance is inversely proportional to area, not directly. A thicker wire (larger AA) has lower resistance. So (A) is false.

  2. Option (B): "decreases with increase in its temperature."

    For most metallic conductors, resistivity ρ\rho increases with temperature (due to increased lattice vibrations scattering electrons). Since R∝ρR \propto \rho, resistance increases with temperature. There are exceptions (semiconductors, certain alloys), but the general rule for conductors is that resistance rises with temperature. So (B) is false.

  3. Option (C): "decreases with increase in its conductivity."

    Conductivity σ=1/ρ\sigma = 1/\rho. If conductivity increases, resistivity decreases. Since R∝ρR \propto \rho, a decrease in ρ\rho means a decrease in RR. So higher conductivity directly implies lower resistance. This is correct. …

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