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Exercise 7.1 · Q25

Q.Find the equation of common tangent to the parabola y2=4xy^2 = 4x and x2=32yx^2 = 32y.

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For y2=4xy^2=4x (a=1a=1), a tangent of slope mm is y=mx+1my=mx+\dfrac1m, so c=1mc=\dfrac1m.

For x2=32yx^2=32y (b=8b=8), a tangent of slope mm is y=mx−bm2=mx−8m2y=mx-bm^2=mx-8m^2, so c=−8m2c=-8m^2. …

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