Skip to content
Exercise 7.1 · Q5

Q.Find co-ordinate of focus, equation of directrix, length of latus rectum and the co-ordinate of end points of latus rectum of the parabola 3y2=−16x3y^2 = -16x.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
3% · 5/151 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

3y2=−16x⇒y2=−163x3y^2=-16x \Rightarrow y^2=-\dfrac{16}{3}x. Compare with y2=−4axy^2=-4ax: 4a=163⇒a=434a=\dfrac{16}{3}\Rightarrow a=\dfrac{4}{3}.

  • Focus (−a,0)=(−43,0)(-a,0)=\left(-\dfrac{4}{3},0\right)
  • Directrix x=a⇒x=43⇒3x−4=0x=a \Rightarrow x=\dfrac{4}{3}\Rightarrow 3x-4=0
  • Length of latus rectum =4a=163=4a=\dfrac{16}{3} …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.