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Exercise 7.1 · Q14

Q.Find coordinate of the point on the parabola y2=12xy^2=12x whose parameter is 1/31/3. Also find focal distance.

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y2=12x⇒4a=12⇒a=3y^2=12x \Rightarrow 4a=12 \Rightarrow a=3.

At t=13t=\dfrac{1}{3}: x=at2=3×19=13x=at^2=3\times\dfrac{1}{9}=\dfrac{1}{3}, y=2at=2×3×13=2y=2at=2\times3\times\dfrac{1}{3}=2.

Point: (13,2)\left(\dfrac{1}{3},2\right). …

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