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Miscellaneous Exercise 7(I) · Q102

Q.If P(π4)P\left(\dfrac{\pi}{4}\right) is any point on the ellipse 9x2+25y2=2259x^2 + 25y^2 = 225. S and S' are its foci then SP⋅S′P=SP \cdot S'P =
A) 13 B) 14 C) 17 D) 19

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9x2+25y2=225⇒x225+y29=19x^2+25y^2=225 \Rightarrow \dfrac{x^2}{25}+\dfrac{y^2}{9}=1, so a2=25, b2=9a^2=25,\,b^2=9.

e2=1−925=1625e^2=1-\dfrac{9}{25}=\dfrac{16}{25}.

For a point at eccentric angle θ\theta, the focal distances are SP=a−e(acos⁡θ)SP=a-e(a\cos\theta) and S′P=a+e(acos⁡θ)S'P=a+e(a\cos\theta), so

SP⋅S′P=a2−e2a2cos⁡2θ=a2(1−e2cos⁡2θ).SP\cdot S'P=a^2-e^2a^2\cos^2\theta=a^2(1-e^2\cos^2\theta). …

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