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Miscellaneous Exercise 7(II) · Q122

Q.Find the equations of the tangents to the parabola y2=9xy^2 = 9x through the point (4,10)(4,10).

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y2=9x⇒a=94y^2=9x \Rightarrow a=\dfrac94. Tangent: y=mx+9/4my=mx+\dfrac{9/4}{m}.

Through (4,10)(4,10): 10=4m+94m⇒40m=16m2+9⇒16m2−40m+9=010=4m+\dfrac{9}{4m} \Rightarrow 40m=16m^2+9 \Rightarrow 16m^2-40m+9=0.

Discriminant =1600−576=1024=322=1600-576=1024=32^2. m=40±3232m=\dfrac{40\pm32}{32}, giving m=94m=\dfrac{9}{4} or m=14m=\dfrac14. …

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