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Exercise 7.1 · Q7

Q.Find the equation of the parabola with vertex at the origin, axis along X-axis and passing through the point (3,4)(3,4).

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Since the axis of symmetry is the XX-axis and the vertex is the origin, the equation is y2=4axy^2=4ax.

The point (3,4)(3,4) lies on it: 42=4a(3)⇒16=12a⇒a=434^2=4a(3) \Rightarrow 16=12a \Rightarrow a=\dfrac{4}{3}. …

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