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Miscellaneous Exercise 7(I) · Q114

Q.The foci of hyperbola 4x2−9y2−36=04x^2 - 9y^2 - 36 = 0 are
A) (±13,0)(\pm\sqrt{13}, 0) B) (±11,0)(\pm\sqrt{11}, 0) C) (±12,0)(\pm\sqrt{12}, 0) D) (0,±12)(0, \pm\sqrt{12})

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4x2−9y2−36=0⇒4x2−9y2=36⇒x29−y24=14x^2-9y^2-36=0 \Rightarrow 4x^2-9y^2=36 \Rightarrow \dfrac{x^2}{9}-\dfrac{y^2}{4}=1, so a2=9, b2=4a^2=9,\,b^2=4. …

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