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MCQ · Q1

Q.If the rms current in a 50 Hz AC circuit is 5 A, the value of the current 1/300 second after its value becomes zero is (A) 52\frac{5}{\sqrt{2}} A (B) 5325\sqrt{\frac{3}{2}} A (C) 56\frac{5}{\sqrt{6}} A (D) 525\sqrt{2} A

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The rms current is given as irms=5i_{rms}=5 A, so the peak current is i0=2 irms=52i_0=\sqrt2\,i_{rms}=5\sqrt2 A. Taking the current to start from zero at t=0t=0 and rise as i=i0sin⁡ωti=i_0\sin\omega t, with ω=2πf=2π(50)=100π\omega=2\pi f=2\pi(50)=100\pi rad/s, the phase at t=1/300t=1/300 s is ωt=100π×1300=π3\omega t=100\pi\times\dfrac{1}{300}=\dfrac{\pi}{3} rad (60∘60^\circ). So i=i0sin⁡(π3)=52×32=562i=i_0\sin\left(\dfrac{\pi}{3}\right)=5\sqrt2\times\dfrac{\sqrt3}{2}=\dfrac{5\sqrt6}{2} A. Simplifying, 562=564=532≈6.12\dfrac{5\sqrt6}{2}=5\sqrt{\dfrac{6}{4}}=5\sqrt{\dfrac{3}{2}}\approx6.12 A. [!ANSWER] (B) 53/25\sqrt{3/2} A ≈6.12\approx6.12 A

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