Q.Calculate the value of capacitance in picofarad, which will make a 101.4 microhenry inductance oscillate with a frequency of one megahertz.
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LC Oscillations: The Electrical Pendulum
Imagine a pendulum. You pull it to one side, storing gravitational potential energy. Release it, and that energy smoothly converts to kinetic energy as it swings through the bottom, then back to potential energy as it rises on the other side. The energy sloshes back and forth at a natural frequency determined by the pendulum's length.
An LC circuit does exactly the same thing — but with electric and magnetic fields instead of height and speed.
The Physical Setup
Take a capacitor (stores energy in an electric field) and an inductor (stores energy in a magnetic field). Connect them in a loop. Initially, charge the capacitor fully — say the top plate is positive, bottom negative. There is no current yet; all the energy is in the capacitor's electric field.
Now close the switch. What happens?
The Oscillation, Step by Step
1. Capacitor discharges through the inductor. The voltage across the capacitor pushes current through the inductor. As current builds up, the inductor resists the change (Lenz's law) — it doesn't let the current jump instantly. The capacitor's electric field collapses gradually, feeding energy into the inductor's magnetic field.
2. Capacitor fully discharged, current at maximum. At this instant, the capacitor has zero voltage. All the energy now resides in the inductor's magnetic field. But the inductor wants to keep current flowing (it opposes a decrease just as it opposed an increase). So the current continues in the same direction.
3. Current charges the capacitor in the opposite polarity. The continuing current pushes charge onto the capacitor plates — now the top becomes negative, bottom positive. The inductor's magnetic field collapses, transferring energy back to the capacitor's electric field. Current decreases until it reaches zero.
4. Capacitor fully charged (opposite polarity), current zero. We're back to the starting situation, but with reversed polarity. The capacitor now discharges again, current flows the opposite way, and the cycle repeats.
The process repeats indefinitely (in an ideal circuit with zero resistance) — energy oscillates between the capacitor and the inductor at a natural frequency.
The Precise Statement
f=2πLC1
This is the natural frequency of free electrical oscillations in an LC circuit. L is inductance in henries, C is capacitance in farads. The period T=2πLC.
Why That Formula?
The derivation comes from equating the two forms of energy and applying Kirchhoff's voltage law. The voltage across the capacitor is V=q/C. The voltage across the inductor is V=−Ldi/dt. In a closed loop:
Cq+Ldtdi=0
Since i=dq/dt, this becomes:
Ldt2d2q+Cq=0
This is the exact same differential equation as a mass on a spring (md2x/dt2+kx=0). The solution is sinusoidal oscillation with angular frequency ω=1/LC, so f=ω/2π=1/(2πLC).
The analogy is exact: L acts like mass (inertia to current change), 1/C acts like spring constant (stiffness against charge separation), and charge q is like displacement x.
Energy Exchange
At any instant, the total energy is constant (in an ideal circuit):
Utotal=21CV2+21LI2=21CV02=21LI02 …
[!TLDR] $f=\dfrac{1}{2\pi\sqrt{LC}}\Rightarrow C=\dfrac{1}{(2\pi f)^2 L}=\dfrac{1}{(2\pi\times10^6)^2(101.4\times10^{ …
Given L = 101.4 μH=101.4×10−6 H, desired resonant/oscillation frequency f=1 MHz =106 Hz. From the LC resonance formula f=2πLC1, squaring and rearranging: C=(2πf)2L1.\n\n(2πf)2=(2×3.1416×106)2=(6.2832×106)2≈3.948×1013.\n\n$C=\dfrac{1}{3.948\times10^{13}\times101.4\tim …
Square the resonant-frequency formula f=1/(2πLC) and rearrange for C=1/[(2πf)2L], …
Forgetting to square 2πf before dividing (i.e. computing C=1/(2πf⋅L) instead of 1/((2πf)2L)), whic …
- CBSE 2026Set DS1 markMCQQ.The unit of LC is:i) secondii) henryiii) faradiv) ampere
›Reveal solutionSolution
LC has the dimensions of time, so its unit is the second.
Concept. The natural (resonant) angular frequency of an LC circuit is ω=LC1. Since ω has units of s−1, the quantity LC must have units of seconds.
…
- CBSE 2024Set ANNUAL1 markMCQQ.In an oscillating LC circuit, the maximum charge on the capacitor is Q. The charge on the capacitor when the energy is stored equally between the electric and magnetic field is :(a) 2Q(b) 2Q(c) Q(d) 3Q
›Reveal solutionSolution
Setting the capacitor's energy equal to half the total (constant) LC-circuit energy gives the charge q=Q/2 at the instant the energy is shared equally.
Working
In an oscillating LC circuit, the total energy is conserved and equals the energy stored when the capacitor is fully charged:
Utotal=2CQ2
At any instant, the energy is shared between the capacitor (electric field) and inductor (magnetic field):
Utotal=2Cq2+21Li2
…
- CBSE 2022Set M1 markQ.Write the expression for the natural frequency of oscillations in an LC circuit.
›Reveal solutionSolution
An LC circuit oscillates at f = 1/(2π√(LC)).
In an ideal LC circuit, energy oscillates between the electric field of the capacitor C and the magnetic field of the inductor L. The angular frequency of these free oscillations is
ω=LC1 …
- CBSE 2020Set ANNUAL1 markMCQQ.In an oscillating LC circuit, the maximum charge on the capacitor is Q. The charge on the capacitor when the energy is stored equally between the electric and magnetic field is :(a) Q(b) 2Q(c) 3Q(d) 2Q
›Reveal solutionSolution
Setting the instantaneous capacitor energy equal to half the total stored energy of the LC oscillator gives the charge q=Q/2.
Working
In an oscillating LC circuit, the total energy oscillates between the capacitor (electric field) and the inductor (magnetic field), with the sum always equal to the maximum energy stored when the capacitor carries the maximum charge Q:
Etotal=2CQ2
At the instant the charge on the capacitor is q, the electric field energy is 2Cq2, and by conservation the magnetic field energy is Etotal−2Cq2.
…
- CBSE 2018Set ANNUAL1 markQ.Match the following (select the appropriate option from Column B for the statement of Column A). Column A: The resonant frequency of an LC circuit. Column B:(i) ω = 1/√(LC),(ii) λ = h/√(2mk),(iii) qvB sinθ,(iv) λ = hν,(v) r = R(E/V − 1),(vi) ε₀A/d.
›Reveal solutionSolution
LC-circuit resonant angular frequency ω = 1/√(LC), option (i).
In a series LC (or LCR) circuit, resonance occurs when the inductive reactance equals the capacitive reactance: X_L = X_C, i.e. ωL = 1/(ωC).
…
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