Skip to content

Physics · Ch 4 — Thermodynamics

Isochoric Process

4.7.3.4

Isochoric Process

An isochoric process (also called an isovolumic process) occurs at constant volume, so ΔV=0\Delta V = 0. Two familiar examples are heating a gas that is sealed inside a rigid, fixed-volume container, and the diffusion of a gas within a closed chamber whose volume cannot change.

Since the volume never changes, the system does no work at all:

W=p ΔV=0(since ΔV=0)W = p\,\Delta V = 0 \qquad (\text{since } \Delta V = 0)

Applying the First Law, Q=ΔU+WQ = \Delta U + W, with W=0W = 0:

Q=ΔU— (4.13)Q = \Delta U \qquad \text{--- (4.13)}

And, as in the isobaric case, the change in internal energy for a fixed volume-heat-capacity is

ΔU=nCV ΔTsoQ=nCV ΔT— (4.14)\Delta U = nC_V\,\Delta T \qquad \text{so} \qquad Q = nC_V\,\Delta T \qquad \text{--- (4.14)}

The physical picture is simple and direct: since the system does no work, every joule of heat added in an isochoric process goes entirely into raising the system's internal energy (and hence its temperature) — none of it is 'diverted' into doing work, unlike in an isobaric process. The temperature of the system does genuinely change (ΔT≠0\Delta T \ne 0) in an isochoric process — only the volume is held fixed. …

Figure 4.17p-V diagram of an isochoric process (an isochore) — a constant-volume change shown as a vertical line between Pi and Pf
Fig. 4.17 — p-V diagram of an isochoric process (an isochore) — a constant-volume change shown as a vertical line between Pi and Pf

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this p-V diagram shows. The graph plots pressure p (vertical axis) against volume V (horizontal axis); the area under the curve equals the work done during the process, and the shape of the path tells you how pressure and volume change tog …