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Q.The refractive indices of water and diamond are 4/34/3 and 2.42 respectively. Find the speed of light in water and diamond. (c=3×108c = 3 \times 10^8 m/s)

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2018Subjective· 3mImportance★★★★★
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Refractive index is defined as n=c/vn = c/v, so the speed of light in a medium is simply v=c/nv = c/n.

The refractive index of a medium is n=cvn = \dfrac{c}{v}, so the speed of light in that medium is v=cnv = \dfrac{c}{n}.

In water (nw=4/3n_w = 4/3):

vw=cnw=3×1084/3=3×108×34=2.25×108 m/s.v_w = \frac{c}{n_w} = \frac{3\times10^8}{4/3} = 3\times10^8\times\frac34 = 2.25\times10^8\ \text{m/s}.

In diamond (nd=2.42n_d = 2.42): …

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