Question 75 of 83
Q.In a biprism experiment, the fringes are observed in the focal plane of the eye-piece at a distance of 1.2 m from the slit. The distance between the central bright band and the 20th bright band is 0.4 cm. When a convex lens is placed between the biprism and the eye-piece, 90 cm from the eye-piece, the distance between the two virtual magnified images is found to be 0.9 cm. Determine the wavelength of light used.
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Combines the biprism fringe-width method with the lens-displacement method for source separation.
Fringe width from the un-lensed setup: with m (slit to eyepiece) and 20 fringes spanning 0.4 cm from the centre,
Source separation from the lens method: the lens is placed 90 cm from the eyepiece, so its distance from the biprism (source) is cm, with cm. The magnification is
The two virtual images (magnified) are separated by cm, so the actual (unmagnified) separation of the two coherent virtual sources is …
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