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Question 67 of 83

Q.In a biprism experiment, light of wavelength 5200 Å is used to obtain an interference pattern on the screen. The fringewidth changes by 1·3 mm when the screen is moved towards the biprism by 50 cm. Calculate the distance between the two virtual images of the slit.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2020Subjective· 3mImportance★★★★★
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Fringe width β = λD/d; use the given change in β for a change in D to solve for d.

Fringe width β=λDd\beta = \dfrac{\lambda D}{d}, so for a fixed dd, a change in screen distance ΔD\Delta D produces a fringe-width change Δβ=λ ΔDd\Delta\beta = \dfrac{\lambda\,\Delta D}{d}. …

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