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Q.A plane wavefront is incident on a concave mirror of radius of curvature RR. The radius of the refracted wavefront will be : (A) 2R2R (B) RR (C) R2\dfrac{R}{2} (D) R4\dfrac{R}{4}

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A plane wavefront has infinite radius of curvature. After reflection from a concave mirror of radius RR, the wavefront becomes spherical with radius equal to half the mirror's radius of curvature, i.e., R2\frac{R}{2}. The correct option is (C).

Concept and Intuition

A wavefront is a surface of constant phase. For a plane wavefront, the rays are parallel, meaning the wavefront has an infinite radius of curvature — it is flat. When such a wavefront strikes a concave mirror, the mirror converges the parallel rays to its focus. The reflected wavefront is therefore spherical, converging to the focal point.

The key relationship: for a spherical mirror, the focal length ff is half the radius of curvature RR:

f=R2f = \frac{R}{2}

The reflected wavefront's radius of curvature is exactly the distance from the mirror to the point where the rays converge — which is the focal point for an incident plane wave. So the reflected wavefront has radius f=R/2f = R/2.

Watch out

A common mistake is to think the reflected wavefront's radius equals the mirror's radius RR. That would be true only if the incident wavefront itself originated from the centre of curvature. Here, the incident wavefront is plane, so the reflected wavefront converges to the focus, not the centre.

Step-by-Step Reasoning

  1. Understand the incident wavefront.

    A plane wavefront means all rays are parallel to the principal axis. The wavefront has infinite radius of curvature: Rincident=∞R_{\text{incident}} = \infty.

  2. Recall the mirror equation in terms of wavefront curvature.

    For a spherical mirror, the relationship between object distance uu, image distance vv, and focal length ff is:

1v+1u=1f\frac{1}{v} + \frac{1}{u} = \frac{1}{f}

For a plane wavefront, the object is at infinity: u=∞u = \infty, so 1u=0\frac{1}{u} = 0. Thus:

1v=1f⇒v=f\frac{1}{v} = \frac{1}{f} \quad \Rightarrow \quad v = f

  1. Relate focal length to radius of curvature. For any spherical mirror:

f=R2f = \frac{R}{2}

Therefore, the image distance for an incident plane wave is:

v=R2v = \frac{R}{2}

  1. Interpret the reflected wavefront. …

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