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MISCELLANEOUS EXERCISE 6 (II) · Q201

Q.Find the range of the following function: f(x)=x9+x2f(x)=\dfrac{x}{9+x^2}.

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Let y=x9+x2y=\dfrac{x}{9+x^2}. Then y(9+x2)=x  ⟹  yx2−x+9y=0y(9+x^2)=x \implies yx^2-x+9y=0, a quadratic in xx (for y≠0y\ne0).

For a real xx to exist, the discriminant must be ≥0\ge0: (−1)2−4(y)(9y)≥0  ⟹  1−36y2≥0  ⟹  y2≤136  ⟹  −16≤y≤16(-1)^2-4(y)(9y)\ge0 \implies 1-36y^2\ge0 \implies y^2\le\dfrac{1}{36} \implies -\dfrac16\le y\le\dfrac16. …

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