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MISCELLANEOUS EXERCISE 6 (II) · Q193

Q.Find the domain of the following function: f(x)=x2+4x+4x2+x−6f(x)=\dfrac{x^2+4x+4}{x^2+x-6}.

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f(x)=x2+4x+4x2+x−6=(x+2)2(x+3)(x−2)f(x)=\dfrac{x^2+4x+4}{x^2+x-6}=\dfrac{(x+2)^2}{(x+3)(x-2)}.

The denominator vanishes at x=−3x=-3 and x=2x=2, so these must be excluded (the numerator's own zero at x=−2x=-2 doesn't …

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