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9.1 · Q13

Q.A room has three sockets for lamps. From a collection 10 bulbs of which 6 are defective. At night a person selects 3 bulbs, at random and puts them in sockets. What is the probability that i) room is still dark ii) the room is lit.

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n(S)=(103)=120n(S)=\binom{10}{3}=120.

i) 'Room still dark' means none of the 3 selected bulbs works, i.e. all 3 are defective: (63)=20\binom{6}{3}=20 ways, P=20/120=1/6P=20/120=1/6. …

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