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9.3 · Q30

Q.A box contains 5 green pencils and 7 yellow pencils. Two pencils are chosen at random from the box without replacement. What is the probability that both are yellow?

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✓ Free question

12 pencils total (5 green, 7 yellow). P(first yellow)=7/12P(\text{first yellow})=7/12. After removing one yellow pencil, 11 remain with 6 yellow, so P(second yellow∣first yellow)=6/11P(\text{second yellow}\mid\text{first yellow})=6/11. By the multiplication theorem, P(both yellow)=712×611=42132=722P(\text{both yellow})=\frac{7}{12}\times\frac{6}{11}=\frac{42}{132}=\frac{7}{22}.

✓Final answer

722\frac{7}{22}.

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