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9.4 · Q54

Q.2% of the population have a certain blood disease of a serious form; 10% have it in a mild form; and 88% don't have it at all. A new blood test is developed; the probability of testing positive is 910\frac{9}{10} if the subject has the serious form, 610\frac{6}{10} if the subject has the mild form, and 110\frac{1}{10} if the subject doesn't have the disease. A subject is tested positive. What is the probability that the subject has serious form of the disease?

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P(+)=0.02(0.9)+0.10(0.6)+0.88(0.1)=0.018+0.06+0.088=0.166P(+)=0.02(0.9)+0.10(0.6)+0.88(0.1)=0.018+0.06+0.088=0.166. By Bayes' theorem, $P(\text{serious}/+)=\dfrac{0.02\times0.9}{0.166}=\dfrac{0.018}{0.166}=\dfr …

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