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Miscellaneous 9 - II · Q82

Q.A die is loaded in such a way that the probability of the face with jj dots turning up is proportional to jj for j=1,2,...,6j = 1, 2, ..., 6. What is the probability, in one roll of the die, that an odd number of dots will turn up?

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Since P(j)=kjP(j)=kj for some constant kk, and probabilities sum to 1, k(1+2+3+4+5+6)=21k=1k(1+2+3+4+5+6)=21k=1, so k=1/21k=1/21 and P(j)=j/21P(j)=j/21. $P(\text{odd})=P(1)+P(3)+P(5)=\dfrac …

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