Skip to content
9.3 · Q41

Q.An urn contains 4 black, 5 white and 6 red balls. Two balls are drawn one after the other without replacement. What is the probability that at least one of them is black?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
76% · 74/97 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Urn has 4+5+6=154+5+6=15 balls, 11 of them non-black. P(no black in 2 draws)=1115×1014=110210=1121P(\text{no black in 2 draws})=\frac{11}{15}\times\frac{10}{14}=\frac{110}{210}=\frac{11}{21}. So $P(\text{at least …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.