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9.4 · Q57

Q.(Activity) Mr. X goes to office by Auto, Car and train. The probabilities of him travelling by these modes are 27\frac{2}{7}, 37\frac{3}{7}, 27\frac{2}{7} respectively. The chances of him being late to the office are 12\frac{1}{2}, 14\frac{1}{4}, 14\frac{1}{4} respectively by Auto, Car and train. On one particular day he was late to the office. Find the probability that he travelled by car. (Complete the following activity.)

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P(A)=2/7,P(Car)=3/7,P(Train)=2/7P(A)=2/7,P(Car)=3/7,P(Train)=2/7; P(L/A)=1/2,P(L/Car)=1/4,P(L/Train)=1/4P(L/A)=1/2,P(L/Car)=1/4,P(L/Train)=1/4. P(L)=27(12)+37(14)+27(14)=17+328+228=428+328+228=928P(L)=\frac{2}{7}(\frac{1}{2})+\frac{3}{7}(\frac{1}{4})+\frac{2}{7}(\frac{1}{4})=\frac{1}{7}+\frac{3}{28}+\frac{2}{28}=\frac{4}{28}+\frac{3}{28}+\frac{2}{28}=\frac{9}{28}. By Bayes' theorem, $P(\text{Car}/L)=\dfrac{(3/7)(1/4)}{9/28}=\dfrac{3/28}{9/28}=\dfr …

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