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Miscellaneous 9 - II · Q83

Q.An urn contains 5 red balls and 2 green balls. A ball is drawn. If it's green a red ball is added to the urn and if it's red a green ball is added to the urn. (The original ball is not returned to the urn). Then a second ball is drawn. What is the probability the second ball is red?

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Urn starts with 5 red, 2 green (7 total). If first drawn is red (prob 5/75/7): removed and a green ball added, leaving 4 red + 3 green = 7; P(second red)=4/7P(\text{second red})=4/7. If first drawn is green (prob 2/72/7): removed and a red ball added, leaving 6 red + 1 green = 7; P(second red)=6/7P(\text{second red})=6/7. By the law of total probability: $$P(\text{ …

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