Q.Distinguish between: Diffusion and osmosis.
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Osmotic Pressure and Molar Mass: From Intuition to Formula
Imagine you have a glass of pure water, and you carefully place a tea bag into it. After a while, the water turns brown. The tea molecules have moved from the bag into the water. That's simple diffusion. But now imagine a different setup: you have a U-shaped tube with a special membrane at the bottom that only lets water molecules pass through — not larger molecules like sugar. On one side you put pure water, on the other side you put a sugar solution. What happens?
Water will spontaneously move from the pure water side into the sugar solution side, pushing the liquid level higher on the sugar side. That rising column of liquid is a direct physical effect — it's osmotic pressure trying to equalise concentrations. The taller the column gets, the more hydrostatic pressure it exerts back. Eventually, that back-pressure exactly balances the "pull" of the sugar, and the system stops.
That balancing pressure — the pressure you would need to apply to the solution side to prevent the water from moving — is the osmotic pressure (Π).
The Intuition Behind Molar Mass from Osmotic Pressure
Here's the key insight: the osmotic pressure depends only on the number of solute particles in a given volume of solution, not on what those particles are. A big protein molecule and a tiny sugar molecule, if present in the same number per litre, produce the same osmotic pressure.
This is incredibly useful. If you dissolve an unknown substance (say, a polymer or a protein) in water and measure the osmotic pressure, you can work backwards to find how many moles of it are present. And if you know the mass you dissolved, you can calculate the molar mass:
Molar mass=number of molesmass of solute (g)
So osmotic pressure becomes a direct window into the molecular weight of substances that are too large or too fragile to vaporise (like proteins, polymers, or enzymes).
The Precise Statement
For dilute solutions, osmotic pressure follows a law that looks exactly like the ideal gas law:
ΠV=nRT
where:
- Π = osmotic pressure (in atm or Pa)
- V = volume of solution (in L or m³)
- n = number of moles of solute
- R = ideal gas constant (0.0821 L·atm·mol⁻¹·K⁻¹ or 8.314 J·mol⁻¹·K⁻¹)
- T = absolute temperature (in K)
This is the van't Hoff equation for osmotic pressure. It tells you that osmotic pressure is directly proportional to the molar concentration of the solute:
Π=VnRT=cRT
where c is the molar concentration (mol/L).
From Osmotic Pressure to Molar Mass
If you dissolve a known mass w (in grams) of an unknown substance in a volume V of solvent, and measure the osmotic pressure Π at temperature T, you can find the molar mass M as follows:
- From ΠV=nRT, we get n=RTΠV
- But n=Mw (mass divided by molar mass)
- Equating: Mw=RTΠV
- Rearranging:
M=ΠVwRT
This is the working formula. Every quantity on the right is measurable in the lab.
Why This Method is Special
Osmotic pressure measurements are extraordinarily sensitive. For a substance with a very large molar mass (say, 100,000 g/mol), the freezing point depression or boiling point elevation would be too tiny to measure accurately. But osmotic pressure can still give a measurable reading because it's a colligative property that depends only on particle count, and the effect is large even at low concentrations.
Osmotic pressure is the most sensitive colligative property for determining molar masses of macromolecules. It can detect concentrations as low as 10−4 M, which is 100–1000 times more sensitive than freezing point depression.
A Worked Example
Problem: 0.50 g of a protein is dissolved in enough water to make 100 mL of solution at 25°C. The osmotic pressure is measured as 0.012 atm. Find the molar mass of the protein.
Solution:
Given: …
Why this formula?
Osmosis: Why the Key Formulas Hold
Osmosis is the net movement of solvent molecules (usually water) across a semipermeable membrane from a region of lower solute concentration to higher solute concentration. The membrane allows solvent to pass but blocks solute.
Let’s build the reasoning step-by-step — from the physical picture to the formulas.
1. The Physical Picture: Why Does Water Move?
Imagine a U-shaped tube divided by a semipermeable membrane. Left side: pure water. Right side: water + dissolved sugar.
- Water molecules on both sides are in constant random motion.
- On the pure water side, every molecule hitting the membrane can pass through (if it fits the pore).
- On the sugar side, sugar molecules block some water molecules from reaching the membrane — effectively reducing the number of water molecules that can cross per second.
Result: More water molecules cross from pure side to sugar side than the reverse. This net flow continues until equilibrium is reached.
Key insight: The driving force is the difference in chemical potential of water across the membrane — not a "desire" to dilute the sugar.
2. Chemical Potential: The Real Driver
For an ideal dilute solution, the chemical potential of water (μw) is:
μw=μw0+RTlnxw
Where:
- μw0 = chemical potential of pure water
- xw = mole fraction of water
- R = gas constant
- T = absolute temperature
Since xw<1 in a solution, lnxw<0, so μw is lower in the solution than in pure water.
Water flows spontaneously from higher μw (pure side) to lower μw (solution side) — this is the fundamental thermodynamic reason.
3. Osmotic Pressure: The Formula Π=iCRT
What is osmotic pressure (Π)?
It is the external pressure that must be applied to the solution side to prevent net water flow into it — i.e., to make the chemical potential of water equal on both sides.
Derivation sketch:
At equilibrium under applied pressure Π:
μwpure(P)=μwsolution(P+Π)
For the solution side, we have two contributions:
- Dilution effect (lower mole fraction): RTlnxw
- Pressure effect: Vw⋅Π (where Vw = partial molar volume of water)
So:
μw0(P)=μw0(P)+RTlnxw+VwΠ
Cancel μw0(P) from both sides:
0=RTlnxw+VwΠ
Π=−VwRTlnxw
For dilute solutions:
- xw≈1−xsolute (where xsolute is small)
- ln(1−xsolute)≈−xsolute (using Taylor expansion)
Thus:
Π≈VwRT⋅xsolute
Now, xsolute=nsolute+nwaternsolute≈nwaternsolute for dilute solutions.
And nwater⋅Vw≈V (total volume of solution).
So:
Π≈VRT⋅nsolute=CRT
Where C=Vnsolute = molar concentration. …
Diffusion is the general movement of any particles (solute or solvent) from high to low concentration, needing no membrane; osmosis is specifically solvent movement across a semipermeable membrane. …
Diffusion is the general movement of any particles (solute or solvent) from high to low concentration, needing no membrane; osmosis is specifically solvent movement across a semipermeable membrane.
Diffusion is the general physical process by which ions, atoms or molecules of any substance move from a region of their higher concentration to a region of their lower concentration, powered purely by the random kinetic energy of the particles, and it can happen in gases, liquids or across freely permeable barriers — no membrane of any particular type is required, and any kind of particle (solute or solvent) can diffuse. …
Distinguish diffusion (general, any particle, no membrane needed) from osmosis (solvent only, requires a semipermeable mem …
- Treating diffusion and osmosis as two entirely unrelated processes, rather than recognising …
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