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Miscellaneous Exercise 3 · Q67

Q.The principal solutions of equation cot⁡θ=3\cot\theta = \sqrt{3} are ____________.

(a) π6,7π6\dfrac{\pi}{6}, \dfrac{7\pi}{6}
(b) π6,5π6\dfrac{\pi}{6}, \dfrac{5\pi}{6}
(c) π6,8π6\dfrac{\pi}{6}, \dfrac{8\pi}{6}
(d) 5π6,7π6\dfrac{5\pi}{6}, \dfrac{7\pi}{6}
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✓ Free question

cot⁡θ=3  ⟹  tan⁡θ=13\cot\theta=\sqrt3\implies\tan\theta=\dfrac1{\sqrt3}, giving θ=π6\theta=\dfrac{\pi}{6} and (adding the tangent period π\pi) θ=7π6\theta=\dfrac{7\pi}{6}, both principal solutions in [0,2π)[0,2\pi).

✓Final answer

(a) π6,7π6\dfrac{\pi}{6},\dfrac{7\pi}{6}

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