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Miscellaneous Exercise 3 · Q81

Q.tan⁡(π4−2tan⁡−115)=\tan\left(\dfrac{\pi}{4} - 2\tan^{-1}\dfrac{1}{5}\right) = __________.

(a) 717\dfrac{7}{17}
(b) 177\dfrac{17}{7}
(c) −717-\dfrac{7}{17}
(d) −177-\dfrac{17}{7}
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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2tan⁡−115=tan⁡−1(2⋅151−125)=tan⁡−1(2/524/25)=tan⁡−15122\tan^{-1}\dfrac15=\tan^{-1}\left(\dfrac{2\cdot\frac15}{1-\frac1{25}}\right)=\tan^{-1}\left(\dfrac{2/5}{24/25}\right)=\tan^{-1}\dfrac{5}{12}. So $\tan\left(\dfrac{\pi}{4}-2\tan^{-1}\dfrac15\right)=\tan\left(\dfrac{\pi}{4}-\tan^{-1}\dfrac{5}{12}\righ …

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