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Miscellaneous Exercise 3 · Q78

Q.If sin⁡−145+cos⁡−11213=sin⁡−1a\sin^{-1}\dfrac{4}{5} + \cos^{-1}\dfrac{12}{13} = \sin^{-1}a, then a=a = _____________.

(a) 6365\dfrac{63}{65}
(b) 6265\dfrac{62}{65}
(c) 6165\dfrac{61}{65}
(d) 6065\dfrac{60}{65}
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Let sin⁡−145=θ\sin^{-1}\dfrac45=\theta (sin⁡θ=45,cos⁡θ=35\sin\theta=\frac45,\cos\theta=\frac35), cos⁡−11213=ϕ\cos^{-1}\dfrac{12}{13}=\phi (cos⁡ϕ=1213,sin⁡ϕ=513\cos\phi=\frac{12}{13},\sin\phi=\frac5{13}). $\sin(\theta+\phi)=\sin\theta\cos\phi+\cos\theta\sin\phi=\dfrac45\cdot\dfrac{12}{13}+\ …

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