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Miscellaneous Exercise 3 · Q90

Q.Find the principal solutions of the equation tan⁡5θ=−1\tan 5\theta = -1

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Let ϕ=5θ∈[0,10π)\phi=5\theta\in[0,10\pi). tan⁡ϕ=−1  ⟹  ϕ=3π4+kπ\tan\phi=-1\implies\phi=\dfrac{3\pi}{4}+k\pi for k=0,1,…,9k=0,1,\ldots,9 (ten copies within [0,10π)[0,10\pi)). Dividing each by 5 gives ten values of θ\theta: 3π20,7π20,11π20,3π4,19π20,23π20,27π20,31π20,7π4,39π20\dfrac{3\pi}{20},\dfrac{7\pi}{20},\dfrac{11\pi}{20},\dfrac{3\pi}{4},\dfrac{19\pi}{20},\dfrac{23\pi}{20},\dfrac{27\pi}{20},\dfrac{31\pi}{20},\dfrac{7\pi}{4},\dfrac{39\pi}{20}. …

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