Skip to content
Miscellaneous Exercise 3 · Q128

Q.Show that tan⁡−112+tan⁡−115+tan⁡−118=π4\tan^{-1}\dfrac{1}{2} + \tan^{-1}\dfrac{1}{5} + \tan^{-1}\dfrac{1}{8} = \dfrac{\pi}{4}.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
72% · 128/177 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

xy=12⋅15=110<1xy=\dfrac12\cdot\dfrac15=\dfrac1{10}<1: tan⁡−112+tan⁡−115=tan⁡−1(12+151−110)=tan⁡−1(7/109/10)=tan⁡−179\tan^{-1}\dfrac12+\tan^{-1}\dfrac15=\tan^{-1}\left(\dfrac{\frac12+\frac15}{1-\frac1{10}}\right)=\tan^{-1}\left(\dfrac{7/10}{9/10}\right)=\tan^{-1}\dfrac79. Now add tan⁡−118\tan^{-1}\dfrac18: xy=79⋅18=772<1xy=\dfrac79\cdot\dfrac18=\dfrac7{72}<1, so $=\tan^{-1}\left(\dfrac{\frac79+\frac18}{1-\frac{7}{72}}\right)=\tan^{-1}\left(\dfrac{56/72+9/72}{65/72}\rig …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.