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Miscellaneous Exercise 3 · Q87

Q.Find the principal solutions of the equation tan⁡3θ=−1\tan 3\theta = -1

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Let ϕ=3θ∈[0,6π)\phi=3\theta\in[0,6\pi). tan⁡ϕ=−1\tan\phi=-1 gives ϕ=3π4+kπ\phi=\dfrac{3\pi}{4}+k\pi for k=0,1,…,5k=0,1,\ldots,5 within [0,6π)[0,6\pi): 3π4,7π4,11π4,15π4,19π4,23π4\dfrac{3\pi}{4},\dfrac{7\pi}{4},\dfrac{11\pi}{4},\dfrac{15\pi}{4},\dfrac{19\pi}{4},\dfrac{23\pi}{4}. Dividing each by 33: $\theta=\dfrac{\pi}{4},\dfrac{7\pi}{12},\dfrac{11\pi}{12},\dfrac{5\pi}{4},\dfrac{19\pi}{12 …

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