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Miscellaneous Exercise 3 · Q73

Q.In △ABC\triangle ABC, if c2+a2−b2=acc^2 + a^2 - b^2 = ac, then ∠B=\angle B = __________.

(a) π4\dfrac{\pi}{4}
(b) π3\dfrac{\pi}{3}
(c) π2\dfrac{\pi}{2}
(d) π6\dfrac{\pi}{6}
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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$c^2+a^2-b^2=ac\implies\cos B=\dfrac{c^2+a^2-b^2}{2ac}=\dfrac{ac}{2ac}=\dfrac12\implies B=\dfrac{ …

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