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Miscellaneous Exercise 3 · Q80

Q.2tan⁡−113+tan⁡−117=2\tan^{-1}\dfrac{1}{3} + \tan^{-1}\dfrac{1}{7} = __________.

(a) tan⁡−145\tan^{-1}\dfrac{4}{5}
(b) π2\dfrac{\pi}{2}
(c) 11
(d) π4\dfrac{\pi}{4}
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2tan⁡−113=tan⁡−1342\tan^{-1}\dfrac13=\tan^{-1}\dfrac34 (shown in Ex.3.3, Q3F). Then tan⁡−134+tan⁡−117\tan^{-1}\dfrac34+\tan^{-1}\dfrac17: xy=34⋅17=328<1xy=\dfrac34\cdot\dfrac17=\dfrac3{28}<1, so $=\tan^{-1}\left(\dfrac{3/4+1/7}{1-3/28}\right)=\tan^{-1}\lef …

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