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Can you tell? 2.3.6 · Q1

Q.What will be the normal atmospheric pressure in bar and also in torr?

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Convert 1.013 × 10⁵ N/m² with the two unit definitions.

Normal atmospheric pressure is 1.013×1051.013\times10^5 N/m². Since 1 bar =105= 10^5 N m⁻², this equals 1.013×105105=1.013 bar\frac{1.013\times10^5}{10^5} = 1.013\ \text{bar} Since one torr is the pressure of 1 mm of mercury and the normal atmosphere supports 76 cm = 760 mm of mercury …

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