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Answer in brief · Q3

Q.Obtain the expression for the period of a simple pendulum performing S.H.M.

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For a simple pendulum of length L and bob mass m, displaced through a small angle θ\theta, the restoring force is F=−mgsin⁡θF=-mg\sin\theta (Eq. 5.26). For small θ\theta (<10°<10°), sin⁡θ≈θ≈x/L\sin\theta\approx\theta\approx x/L (x = arc-length displacement), so F=−mgxLF=-\frac{mgx}{L} (Eq. 5.27) -- proportional to and opposite to x, confirming S.H.M. Using F=maF=ma, the acceleration is a=−gLxa=-\frac{g}{L}x, so the acceleration-per-unit-displacement is g/Lg/L. …

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